a carnot engine takes 3x10^6 cal of heat from a reservoir at 627 degrees celsius and gives it to a sink at27
Answers
Answered by
8
The formular is Qres/Qsink=Tres/Tsink
T(Kelvin scale)=T+273
Calculate Qsink first & then work
W=Q res-Qsink
T(Kelvin scale)=T+273
Calculate Qsink first & then work
W=Q res-Qsink
Similar questions