a carnot engine takes heat from a reservoir at 627 degree celsius and rejects heat to a sink at 27 degree celsius . its efficiency will be
Answers
Answered by
4
Answer:
-2
Explanation:
t1=627+273=900
t2=27+273=300
efficiency of carnot engine is
=t1-t2÷t1
=1-t2÷t1
=1-900÷300
=1-3
=-2
Answered by
0
Answer:
-2
Explanation:
t1=627+273=900
t2=27+273=300
efficiency of carnot engine is
=t1-t2÷t1
=1-t2÷t1
=1-900÷300
=1-3
=-2
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