Question

a carnot engine takes heat from a reservoir at 627 degree celsius and rejects heat to a sink at 27 degree celsius . its efficiency will be

Answer 1

Answer:

-2

Explanation:

t1=627+273=900

t2=27+273=300

efficiency of carnot engine is

=t1-t2÷t1

=1-t2÷t1

=1-900÷300

=1-3

=-2

Answer 2

Answer:

-2

Explanation:

t1=627+273=900

t2=27+273=300

efficiency of carnot engine is

=t1-t2÷t1

=1-t2÷t1

=1-900÷300

=1-3

=-2