A carnot engine whose heat sink is at 27° has an efficiency of 40%. by how many degrees should the temperature of source be changed to increase the efficiency by 10% of the original efficiency? (
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Answered by
28
answer is 35.7 k
which is equal to 35.7 degree celcius also because change is same at both degree celcius and kelvin scales
which is equal to 35.7 degree celcius also because change is same at both degree celcius and kelvin scales
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Answered by
17
Mark it as brainlist ans
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