A carnot engine working between 300k and 600k its efficiency
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Answered by
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Efficiency=1 - T1/T2
T1=300 K
T2=600 K
Therefore,
Efficiency η = 1 - 300/600
=>η = 1 - 0.5
Hence,
η = 0.5
= 50%
....
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T1=300 K
T2=600 K
Therefore,
Efficiency η = 1 - 300/600
=>η = 1 - 0.5
Hence,
η = 0.5
= 50%
....
Please mark my answer as brainliest.
Follow my account for more instant and right answers.
Thank You.
Have a great day ahead.✌✌✌✌✌✌✌✌✌
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4
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