Question

A carnot engine works aa a refrigerator between 250k and 300k . It it receives 750cal of heat from the reservoir at the lower temperature. Calculate the amount of heat rejected at the higher temperature ?

Answer 1

Answer:

Explanation:

Here is the solution to the above question:

Q2/Q1 = T2/T1 = 250/300 = 5/6

Q2 = 500 cal

Q1 = 600 cal

W = Q1-Q2 = 100 cal