A carpenter swings a 3-kg hammer so that its speed is 5 m/s just before it strikes a nail. the nail is driven 6 mm into a block of wood. assuming that a constant force resisted the motion of the nail, what must have been the magnitude of the force?
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According to question
Mass of Hammer M = 3 Kg
Speed of Hammer v = 5 m/sec
Distance = v /t
6 mm = 5/t
0.006 = 5/t
t = 83 sec
Thus acceleration = v/t = 5/83 = 0.06 m/s^2
Thus
F = M * a
= 3 * 0.06
= 0.18 N
Mass of Hammer M = 3 Kg
Speed of Hammer v = 5 m/sec
Distance = v /t
6 mm = 5/t
0.006 = 5/t
t = 83 sec
Thus acceleration = v/t = 5/83 = 0.06 m/s^2
Thus
F = M * a
= 3 * 0.06
= 0.18 N
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