a carriage moves with a velocity of 40 m/s is brought to rest in 5 sec . calculate its speed in m/s
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given, initial velocity u= 40 km/s, time t= 5 s, final value v= 0 (rest)
suppose acceleration = - a(deacceleration)
from first law of motion v= u-a*t
0= 40 - a*5,
suppose traveled distance = S
from second law of motion S= u*t - 1/2*a*t^2
S= 40*5 - 1/2*4*5^2
S= 100 m/s
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suppose acceleration = - a(deacceleration)
from first law of motion v= u-a*t
0= 40 - a*5,
suppose traveled distance = S
from second law of motion S= u*t - 1/2*a*t^2
S= 40*5 - 1/2*4*5^2
S= 100 m/s
MARK AS BRAINLIEST
yamunadevimuthu:
actually ur answer is wrong
first we want to km to m , hour to seconds
30,000 ÷ 3600
answer is 8.33
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