Question

A cart of mass 50 kg is moving on a straight track with a speed of 12 m/s. A mass of 10 jg is gently put into the cart. What will be the velocity of the cart.

Answer 1

Answer:

Mass of cart , M = 50 kg and speed of cart, V = 12m/s

Let mass m=10 kg put into cart with speed v

According to law of conservation of momentum (newton's second law)

MV=mv

50 x 12 = (50+10) x v

v = 10 m/s

now velocity of cart after put 10 kd is 10 m/s

i hope it will help you

regards

Answer 2

Explanation:

:

Given : -

• a cart with a mass of 12 kg

• traveling at 15 m/s .

• slows down to 11 m/s in 12 seconds.

To Find : -

• What would be the acceleration of the cart?

• What would be the net force on the cart during this time?

Solution : -

we have :

What would be the acceleration of the cart?

v = u + at

Substitute all values :

11 = 15 + a × 12

- 12a = 15 - 11

- 12a = 4

a = - 4 / 12

a = 0.33

What would be the net force on the cart during this time?

We have :

F = ma

F = 12 × 1/3

F =12 /3

F = 4 N