Question

A cast iron block of 5 sq cm cross section carries an axial load of 10t. Maximum shear stress in the block is

Answer 1

so you know, about shear stress ?
actually, shear stress is the ratio of axial load to cross sectional area of block .

e.g., shear stress = axial load/cross sectional area

given, axial load = 10N [ I think here you should write 10N in place of 10t]

cross sectional area = 5cm² = 5 × 10^-4 m²

shear stress = 10N/(5 × 10^-4 m²)

= 2000 N/m²

hence, maximum shear stress in the block is 2000N/m²

Answer 2

Answer:

1000kg/sq.cm

Explanation:

shear stress =axial load/cross section area

                   =10*1000/5 sq.cm   (1t=1000kg)

                    =2000kg/sq.cm

( σx=2000, σy=0,τxy=0) using the formula i have kept in the image  substitute the values and you we will get maximum shear

maximum shear stress in the block=$}\sqrt{(2000-0/2)^{2}+0^{2} }$

                                                         =1000 kg/sq.cm