how many terms of gp 2/9,-1/3,1/2...must be added to get the sum equal to to 55/72
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Let's assume, we take ’n' terms
Sn = {a(1-r^)} / (1-r) , where, Sn denotes the sum of n terms, ‘a’ is the first term.of GP, & r is common ratio. Here, a= 2/9, r = -1/3 ÷ 2/9 = -3/2
=> 55/72 = {2/9 (1- (-3/2)^n ) } / { 1 - (-3/2) }
=> 55/72 = {2/9 ( 1 + (3/2)^n) / 5/2
=>( 55 * 5 * 9)/(72 * 2 *2) = (1+(3/2)^n )
=> (275/32) - 1 = (3/2)^n
=> 243/32 = (3/2)^n
=> (3/2)^5 = (3/2)^n
=> n = 5
5 terms to be taken
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