Write the products of electrolysis of aqueous solution of nacl with platinum electrodes.
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Answered by
52
Hey buddy,
● Electrolysis of NaCl(aq) -
When aquous sodium chloride undergo electrolysis in presence of platinum electrodes, the reaction is follows-
NaCl ---> Na+ + Cl-
H20 ---> H+ + OH-
At anode, Cl- ions are discharged in preference to OH- ions.
Cl- ---> (1/2)Cl2 + e-
At cathode, H+ ions are discharged in preference to Na+ ions.
H+ + e- ---> (1/2)H2
Overall reaction is -
NaCl + H20 ---> Na+ + OH- + (1/2)H2 + (1/2)Cl2
Hope this is helpful...
● Electrolysis of NaCl(aq) -
When aquous sodium chloride undergo electrolysis in presence of platinum electrodes, the reaction is follows-
NaCl ---> Na+ + Cl-
H20 ---> H+ + OH-
At anode, Cl- ions are discharged in preference to OH- ions.
Cl- ---> (1/2)Cl2 + e-
At cathode, H+ ions are discharged in preference to Na+ ions.
H+ + e- ---> (1/2)H2
Overall reaction is -
NaCl + H20 ---> Na+ + OH- + (1/2)H2 + (1/2)Cl2
Hope this is helpful...
Answered by
16
Electrolysis of NaCl(aq) with platinum electrodes,
When aquous solution of sodium chloride undergoes electrolysis in presence of platinum electrodes, the reaction is as below,
NaCl ---> Na+ + Cl-
H20 ---> H+ + OH-
At anode, Cl- ions are discharged in preference to OH- ions as oxidation potential of chlorine is higher than hydroxyl ion.
Cl- ---> (1/2)Cl2 + e-
At cathode, H+ ions are discharged in preference to Na+ ions as the reduction potential of H+ is higher than Na+ ion.
H+ + e- ---> (1/2)H2
The Overall reaction is -
NaCl + H20 ---> Na+ + OH- + (1/2)H2 + (1/2)Cl2
Read more on Brainly.in - https://brainly.in/question/7391587#readmore
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