Question

A cat of body mass 2.5 kg running with a speed of 2m/s jumps on a stationary skateboard of mass 0.5 kg. Will the

skateboard move with a cat on it if yes then find the velocity of

the board and cat system?​

Answer 1

Answer:

Yes,velocity=5/3m/s

Explanation:

m1=2.5kg

u1=2m/s

m2=0.5kg

u2=0

m3=m1+m2=3kg

According to the conservation of linear momentum.

m1u1+m2u2=m3v3

5+0=3v3

v3=5/3m/s

Answer 2

Yes, the skateboard will move like a cat with a velocity of 5/3 m/s.

GIVEN: A cat with a body mass of 2.5 kg running with a speed of 2m/s jumps on a stationary skateboard of mass 0.5 kg.
TO FIND: Will the skateboard move with a cat on it if yes then find the velocity of the board and cat system
SOLUTION:

As we are given in the question,

Body mass of Cat = 2.5kg.

Speed of cat = 2m/s

Mass of stationary skateboard =  0.5kg

So now,

m1=2.5kg

u1=2m/s

m2=0.5kg

u2=0

So,

m3=m1+m2=3kg

Now,

According to the law of conservation of linear momentum.

m1u1+m2u2=m3v3

5+0=3v3

v3=5/3m/s

Therefore,

Yes, the skateboard will move like a cat with a velocity of 5/3 m/s.

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