Question

A cat running at a speed of 2 metre per second accelerates at a constant rate of 1.5 metre per second square for the 5 second. calculate the distance covered by the cat from its initial position and the final velocity of cat.​

Answer 1

Answer:

Explanation:

1.

S=ut + 1/2 at^2

S= 2*5 + 1/2 *1.5*5*5

S = 10 +  18.75

S = 28.75 (distance)

2.

V= u+at

V= 2+ 1.5*5

V= 9.5 ( final velocity)