a catapult on an aircraft carrier is capable of accelerating a plane from 0 to 56 m/s in a distance of 80 m. which is the acceleration of the plane being launched?
Answers
Answered by
3
Intial Velocity(u)= 0 m/s
Final Velocity (v)=56m/s
Distance (s)=80 METRES
Accerlation (a)=??
Using Netwon second equation of motion
v²=u²+2as
56²=0²+2a×80
56²-0²=80a
80a=3136
a=3136÷80
a=39.2
Accerlation of plane at launching=39.2 ms²
Hopes help you
Thanks
Final Velocity (v)=56m/s
Distance (s)=80 METRES
Accerlation (a)=??
Using Netwon second equation of motion
v²=u²+2as
56²=0²+2a×80
56²-0²=80a
80a=3136
a=3136÷80
a=39.2
Accerlation of plane at launching=39.2 ms²
Hopes help you
Thanks
Answered by
1
ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓ
ⓗⓔⓡⓔ ⓘⓢ ⓨⓞⓤⓡ
ⓐⓝⓢⓦⓔⓡ
======================================
⊙ u = 0 m/s
⊙ v = 56 m/s
⊙ s = 80 m
⊙ a = ?
using the third equation of motion
3136= 2*80*s
160s = 3136
s = 3136 / 160 = 19.6 meter
Hope it helps you
@ Prabhudutt
ⓗⓔⓡⓔ ⓘⓢ ⓨⓞⓤⓡ
ⓐⓝⓢⓦⓔⓡ
======================================
⊙ u = 0 m/s
⊙ v = 56 m/s
⊙ s = 80 m
⊙ a = ?
using the third equation of motion
3136= 2*80*s
160s = 3136
s = 3136 / 160 = 19.6 meter
Hope it helps you
@ Prabhudutt
Similar questions