Physics, asked by narayanaraopkl12671, 1 year ago

a catapult on an aircraft carrier is capable of accelerating a plane from 0 to 56 m/s in a distance of 80 m. which is the acceleration of the plane being launched?

Answers

Answered by pratyush4211
3
Intial Velocity(u)= 0 m/s
Final Velocity (v)=56m/s
Distance (s)=80 METRES
Accerlation (a)=??

Using Netwon second equation of motion
v²=u²+2as
56²=0²+2a×80
56²-0²=80a
80a=3136
a=3136÷80
a=39.2

Accerlation of plane at launching=39.2 ms²

Hopes help you
Thanks
Answered by Anonymous
1
ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓ

ⓗⓔⓡⓔ ⓘⓢ ⓨⓞⓤⓡ

ⓐⓝⓢⓦⓔⓡ

======================================

⊙ u = 0 m/s

⊙ v = 56 m/s

⊙ s = 80 m

⊙ a = ?

using the third equation of motion

v {}^{2} = u {}^{2} + 2as

3136= 2*80*s


160s = 3136


s = 3136 / 160 = 19.6 meter




Hope it helps you

@ Prabhudutt
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