Question

A cavity of radius r / 2 is made inside a solid sphere of radius r the centre of the cavity is located at a distance r / 2 from the centre of the sphere the gravitational force on a particle of mass m at a distance r / 2 from the centre of the sphere on the joining was centres of sphere and cavity

Answer 1

Thank you for asking this question. Here is your answer:

The options for this question are missing, here are the missing options:

A) mg/2

B) 3mg/8

C) mg/16

D) None of these

Answer:

E₁ = Pr/3ε₀ = pR/6ε₀ ... [ε₀ = 1/4πG]

E₂ = (-p)(R/2)³ r/3ε₀ R² ....  [using E = pa³/3ε₀r²

- (-p) R³ / 24ε₀R² = - -pR/24ε₀

E = E₁ + E₂ = pR/6ε₀ - pR/24ε₀ = pR/8ε₀

Net force m --> F = mE = mpR/8ε₀

p = M/(4/3) πR³ and ε₀ = 1/4πG

F = 3mg/8

If there is any confusion please leave a comment below.

Answer 2

Answer: Plz refer the picture hope this helps

Explanation: