A cavity of radius r / 2 is made inside a solid sphere of radius r the centre of the cavity is located at a distance r / 2 from the centre of the sphere the gravitational force on a particle of mass m at a distance r / 2 from the centre of the sphere on the joining was centres of sphere and cavity
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16
Thank you for asking this question. Here is your answer:
The options for this question are missing, here are the missing options:
A) mg/2
B) 3mg/8
C) mg/16
D) None of these
Answer:
E₁ = Pr/3ε₀ = pR/6ε₀ ... [ε₀ = 1/4πG]
E₂ = (-p)(R/2)³ r/3ε₀ R² .... [using E = pa³/3ε₀r²
- (-p) R³ / 24ε₀R² = - -pR/24ε₀
E = E₁ + E₂ = pR/6ε₀ - pR/24ε₀ = pR/8ε₀
Net force m --> F = mE = mpR/8ε₀
p = M/(4/3) πR³ and ε₀ = 1/4πG
F = 3mg/8
If there is any confusion please leave a comment below.
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Answer: Plz refer the picture hope this helps
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