A CD has a radius of 21 cm.There is a hole in the middle of the CD which has a radius of 14 cm.find the area of the CD.
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5
area of big CD= πr2
area of am CD=πr2
hence required area is π(r12-r22)
π(441-196)
π(245)
area of am CD=πr2
hence required area is π(r12-r22)
π(441-196)
π(245)
Answered by
23
Thus,Area of the CD is 770
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