Question

A cell has an emf 1.5v and internal resistance of 1 ohms. It is connected to 2 resistors of resistance 2 ohms and 3 ohms in series. Calculate the current flowering in the circuit

Answer 1

v=I(R1+R2+R3+r)

1.5=I=(2+2+3+1)

I=(1.5/8) amp

I=0.1875 amp