A cell of e.m.f 2V and internal resistance 0.2 Ω is connected to a 3.8Ω external resistance. Calculate the terminal voltage.. Please answer it fast...
Answers
Answered by
1
Answer:
terminal voltage =0V
Explanation:
Given:
e.m.f=2V
internal voltage=0.2ohm
external resistance =3.8ohm
Total resistance=internal +external resistance
=0.2+3.8
=4 ohm
I=e.m.f/total resistance
I=2/4=0.5A
I=0.5
terminal voltage = e.m.f-IR
= 2-(0.5×4)
=2-2
=0
Similar questions