Physics, asked by umakantkumar950, 1 year ago

A cell of EMF 1.5 volt is connected with an ammeter of resistance 0.05 ohm if the current in the circuit is 2.0 ampere the internal resistance of the cell is

Answers

Answered by mohitjoshi560
9
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Answered by hood70073
3

Answer:

we know that

E = i(R+r)

1.5= 2(0.05+r)

1.5/2= 0.05+r

0.75=0.05+r

r = 0.75-0.05

r =0.70 ohm

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