A cell of EMF 1.5 volt is connected with an ammeter of resistance 0.05 ohm if the current in the circuit is 2.0 ampere the internal resistance of the cell is
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umakantkumar950:
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we know that
E = i(R+r)
1.5= 2(0.05+r)
1.5/2= 0.05+r
0.75=0.05+r
r = 0.75-0.05
r =0.70 ohm
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