Question

A cell of EMF 1.5 volt is connected with an ammeter of resistance 0.05 ohm if the current in the circuit is 2.0 ampere the internal resistance of the cell is

Answer 1

Please find the answer attached and mark as brainliest if possible

Answer 2

Answer:

we know that

E = i(R+r)

1.5= 2(0.05+r)

1.5/2= 0.05+r

0.75=0.05+r

r = 0.75-0.05

r =0.70 ohm