Question

A constant force acts on an object of mass 3.2kg for a duration of 6s. It increases the velocity from 2.5m/s to 9m/s. Find the magnitude of the force

Answer 1

Given,
m = 3.2 kg
t = 6s
u = 2.5 m/s
v = 9 m/s

We know that,
F = m ( v - u) / t

So,
Force
= 3.2 ( 9 - 2.5 ) / 6
= 3.46 N

Therefore, A force of 3.46 N is exterted on the body.

The magnitude of force is 3.46 N

Answer 2

HOLA!!

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HERE WE GO

GIVEN

Mass (m) = 3.2 kg

Time (t) = 6s

Initial Velocity ( u) = 2.5ms^-1

Final Velocity (v) = 9ms^-1

Force = ?

SOLUTION

Force = m(v-u)/t

= 3.2kg ( 9 - 2.5)/ 6

= 3.2 (6.5)/6

= 20.8/6

= 3.46666N

THEREFORE

Magnitude of Force = 3.466N

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HOPE IT IS HELPFUL!!!!