A cell of emf 2v and internal resistance 0.1 ohm is connected to 20 ohm resistor . What is the current in the circuit?
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EXPLANATION.
emf of the cell is 2v.
Internal resistance is 0.1 Ω.
Resistor is 20Ω.
As we know that,
Formula of :
Current = (emf)/(Resistance + internal resistance).
⇒ i = E/(Req).
Req = Resistance + internal resistance.
⇒ Req = 20Ω + 0.1Ω.
⇒ Req = 20.1Ω.
⇒ E = 2 v.
⇒ i = 2/(20.1).
⇒ i = 0.099 A.
∴ The current in the circuit is i = 0.099 A.
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