Question

A cell of emf 3v and internal resistance 4ohm is connected to two resistance 10ohm and 24ohm joined in parallel. Find the current through each resistance using kirchoffs laws

Answer 1

Answer:

emf=3V

r{internal resistance} = 4 ohm

R1=10 OHMS

R2=24 OHMS

I=?

V=3

Explanation:

v=IR

I=V/R

so we have to find out the value of R

TO FIND RESISTIVITY

R1R2/R1+R2

10[24]/10+24

240/34=7.0588

then subsititute in formulae

I=V/R

I= 3/7.0588=0.42500141667