Question

A cell of emf 4 voltage and internal resistance 1 ohm is connected to a dc source of 10 voltage through a resistance of 5 ohm calculate the terminal voltage across the cell during charging

Answer 1

Answer:

See below.

Explanation:

See the diagram attached to the answer.

Applying Kirchoff's Voltage Law in loop ABCDA,

$\begin{aligned}10+5i+i+4=0\\ \Rightarrow \left| i\right| =\dfrac {7}{3}A\end{aligned}$

Therefore, P.D across the cell with EMF = 4 V,

$\begin{aligned}V=\varepsilon -ir\\ = 4-\dfrac {7}{3}\left( 1\right) \\ = \dfrac {5}{3} V\end{aligned}$

Answer 2

Explanation:

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