A cell of emf (E) and internal resistance r is connected across a variable
external resistance R. The graph of terminal potential difference V as a
function of R is ?
I have attached the graphs too pls tell me which one is the answer ?
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Answered by
4
Answer:
Heyy mate ...
Here is your answer
Explanation:
yesterday I aslo given exam so I tick the option c
But I search it on google then there is correct option is (B)
Hope it's help you.
Answered by
0
Answer:
Explanation:
Here the terminal voltage , V=E−ir...(1) and the current i=E/(R+r)
Now, V=E−
(R+r)
E
r=
R+r
ER
=
(1+r/R)
E
=...(2)
According to equation (1) and (2), the graph V vs i and V vs R will be as shown in figure.
As i=E/(R+r) so 1=E/(4+r) or E=4+r...(3) and
0.5=E/(9+r) or 2E=9+r....(4)
using (3), 2(4+r)=9+r or r=1Ω
Thus, E=4+1=5V
solution
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