A cell of internal resistance r passes current for some time in a resistor R1. In another resistor R2 current is passed for the same time. If same heat is produced in tge two resistor then show that r =√R1R2.
Answers
Answered by
3
Proved that r = √ R1R2
Explanation:
According to the statement of the question:
εlo^2R1 / (R1+r)^2 = εlo^2R2 / (R2+r)^2
Heat (E) = VIt = I^2Rt
E1 = [ε / (R +r)]^2R1t
E2 = [ε / (R2 +r)]^2R2t
E1 = E2
=> [ε / (R1 +r)]^2R1t = [ε / (R2 +r)]^2R2t
=> (R2 +r)]^2R1 = (R1 +r)]^2R2
=> (R2^2 + r^2 2R2r)R1 = (R1^2 +r^2 + 2R1r)R2
=> R2R1 ( R2 - R1 ) = r^2 (R2 - R1)
r = √ R1R2
Hence proved that r = √ R1R2
Also learn more
A 200 ohm resistor is connected in series with a 5 micro meter of capacitor .The voltage across the resistor is Vr=(1.20 V) cos (2500 rad/s)t.capacitive Reactance is ?
https://brainly.in/question/12853960
Similar questions