Question

a cell of potential difference 6V is connected to a bulb. the bulb draws 0.5 A current while glowing find the resistance of the bulb​

Answer 1

Given:

• Potential difference of cell, V = 6 V
• Current drawn by bulb while glowing, I = 0.5 A

To find:

• Resistance of Bulb, R = ?

Formula required:

• Expression of Ohm's Law

          V = I R

[ Where V is potential difference, I is the current and R is resistance ]

• SI unit of Resistance is Ohm (Ω)
• SI unit of Potential difference is Volts (V)
• SI unit of current is Ampere (A)

Calculation:

Using expression for ohm's law

→ V = I R

→ 6 = 0.5 × R

→ R = 6 / 0.5

→ R = 60 / 5

→ R = 12 Ω

• Therefore, Resistance of bulb is 12 ohms.

Answer 2

Answer:

✡ Given ✡

$\mapsto$ A cell of potential difference 6V is connected to a bulb.

$\mapsto$ The bulb draws 0.5 A current while glowing.

✡ To Find ✡

$\mapsto$ What is the value of resistance(R) of the bulb.

✡ Formula Used ✡

✴ V = I R ✴

Where,

• V = Voltage
• I = Current
• R = Resistance

✡ Solution ✡

Given:-

• Voltage (V) = 6V
• Current (I) = 0.5 A

▶ According to the formula,

$\implies$ 6 = 0.5 × R

$\implies$ R = $\dfrac{6}{0.5}$

$\implies$ R = $\dfrac{6 × 10}{5}$

$\implies$ R = 12 $\Omega$

Hence, the resistance (R) of the bulb is 12 ohms.

Explanation:

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