Question

A cell supplies a current i, through a resistance R, and a current i, throufh a resistance R . The internal
resistance of the cell is
1) R2-R
iR2-IR
2)
i-i
i_R2-IR
3)
i-i,
4)
(1+i)R,
i-i,​

Answer 1

Answer:

) {(I2R2 – I1R1)/(I1 – I2)}

Explanation:

HEY MATE ..

Explanation: Let E be emf of a cell then E = I1(R1 + r) E = I2(R2 + r) ∴ I1(R1 + r) = I2(R2 + r) I1r – I­2r = I2R2 – I1R1 r = {(I2R2 – I1R1)/(I1 – I2)}

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