A cell supplies a current of 0.15(A) through a 7.5(hm) and a current of 0.10(A) through a 10.5(hm) wire. find the EMF and internal resistance of the cell.
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The current in the circuit is the result of total voltage divided by total resistance in the circuit. Therefore the total resistance equals the 4ohms plus 0.5 ohms =4.5ohms
The current is 3V/4.5ohms =0.667A
The terminal resistance is the voltage across the load and for this case we use a voltage divider:
4/4.5 times 3V =2.67V
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