A cement block of weight 100N has a sides of length 10cm,20cm and 24cm.Calculate the pressure exerted by the when it is lying on the side with the ;
i.least area ii.greatest area.
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Answer:
(i) 5000Pa
(ii)2083Pa
Explanation:
Force = 100N
Least area = 10cm*20cm=200cm^2=0.02m^2
Greatest area =20cm*24cm = 480cm^2 = 0.048cm^2
Pressure=Force/Area
Least Area Pressure=100N/0.02m^2=5000N/m^2=5000Pa
Greatest area pressure=100N/0.048m^2=6250N/3m^2=2083Pa
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