Question

A centrifugal pump delivers water at the rate of 50 litres/s against a total head of 40 metres. then the power required to drive the pump is

Answer 1

 
 P. Curtis1. Reaction steam turbine

 

Q. Rateau2. Gas turbine

 

R. Kaplan3. Velocity compounding

 

S. Francis4. Pressure compounding

 

5. Impulse water turbine

 

6. Axial turbine

 

7. Mixed flow turbine

 

8. Centrifugal pump

 

Answer 2

Answer:

The power required to drive the pump is 20kN.

Explanation:

The power is given as,

$P=\frac{mgh}{t}$         (1)

Where,

P=power required

m=mass of the body

g=acceleration due to gravity=10m/s²

h=height to which the body is raised

t=time required

Mass in terms of density can be written as,

$m=\rho\times V$         (2)

ρ=density of the water=1000kg/m³

V=volume occupied by the water

By substituting equation (2) in the equation (1) we get;

$P=\frac{\rho\times V \times g\times h}{t}$         (3)

From the question we have;

$\frac{V}{t}$=50L/s=50×10⁻³m³s⁻¹                   (1L=1×10⁻³m³)

h=40m

By substituting the required values in equation (3) we get;

$P=1000\times 50\times 10^-^3\times 10\times 40=50\times 10\times 40=20000N=20kN$    

Hence, the power required to drive the pump is 20kN.