Question

a certain amount of gas at 25 degree Celsius and at a pressure of 0.80 ATM is contained in a glass vessel suppose that the vessel can with stand a pressure of 2.0 ATM how high you can raise the temperature of the gas without bursting the vessel

Answer 1

Answer:- 745 K

Explanation: Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$     (At constant volume and number of moles)

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where P = pressure in atm

T= temperature in Kelvin

Given:

$P_1=0.80 atm$

$T_1=25^0C=25+273K=298K$

$P_2=2.0 atm$

$\frac{0.80atm}{298K}=\frac{2.0 atm}{T_2}$

$T_2=745K$

Answer 2

Explanation:

472 is right answer thes is correct