Area of square field of side 3xy²
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5
Area of square = ( side) ^ 2
=(3xy²)²
=(3xy²)* (3xy²)
=9x²y⁴ sq.units
Therefore,Area of square field of side 3xy² is 9x²y⁴ sq.units
=(3xy²)²
=(3xy²)* (3xy²)
=9x²y⁴ sq.units
Therefore,Area of square field of side 3xy² is 9x²y⁴ sq.units
suzenkhan043:
Area of square =side^2
Answered by
1
Heya kavya
We know that area of square is the square of its side.
Area = s ^2
Here side = 3xy^2 (given)
Area = [3x(y^2)]^2
= 9x^2y^4 sq.units
Hope this helps dear
We know that area of square is the square of its side.
Area = s ^2
Here side = 3xy^2 (given)
Area = [3x(y^2)]^2
= 9x^2y^4 sq.units
Hope this helps dear
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