A certain amount of NaOH is dissolved in certain kilograms of solvent and molality of the solution is '0.5 m' . When the same amount of NaOH is dissolved in "100 grams of less solvent than initial" then molality becomes '0.625 m'. Determine the amount of NaOH and the initial mass of solvent . Proper explanation expected. Best of luck guys ! :)
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sorry bro I don't know the answer really sorry
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