A certain force acting on a mass of 15kg for 3s, gives it a velocity of2m/s. Find the magnitude of force
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Answered by
59
u=0
v = 2 m/s
t = 3s
as, v = u +at
⇒2 = 3a
⇒a = 2/3 m/s²
Force = mass×acceleration
= 15×(2/3) = 10 N or 10 Kg m/s²
v = 2 m/s
t = 3s
as, v = u +at
⇒2 = 3a
⇒a = 2/3 m/s²
Force = mass×acceleration
= 15×(2/3) = 10 N or 10 Kg m/s²
Answered by
8
ANSWER:
10 N is the magnitude of force.
EXPLANATION:
In the given question the Initial velocity u is equal to zero and the final velocity V is equal to 2 meter per second. Time being 3 second. To first define acceleration we have to use Newton's Law of Motion V = U+at
Putting the values in the above equation we get,
Hence we get acceleration as meter per Second Square.
Now to find force we have to apply the formula
F= ma {Where f is force, M is mass, and a is acceleration}
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