A certain force acts on a body of mass 10 kg and changes its velocity from 2 metre per second to 5 metre per second calculate the work done by the force.
Answers
Answered by
2
Answer:
30 N
Explanation:
F=m*a
here acceleration is 3m per second so we get
F=10*3
=30N
Answered by
2
Explanation:
Work done = change in kinetic energy
= ½ m(v2 - v1)
= ½ × 10 (5 - 2)
= 5(3)
= 15 J
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