Physics, asked by tripti38, 10 months ago

A certain force acts on a body of mass 10 kg and changes its velocity from 2 metre per second to 5 metre per second calculate the work done by the force.

Answers

Answered by surendhar76

2

Answer:

30 N

Explanation:

F=m*a

here acceleration is 3m per second so we get

F=10*3

=30N

Answered by deepsen640

2

Explanation:

Work done = change in kinetic energy

= ½ m(v2 - v1)

= ½ × 10 (5 - 2)

= 5(3)

= 15 J

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