Question

A certain force acts on a body of mass 10 kg and changes its velocity from 2 ml to 5 m s. Calculate the work done by the force.

Answer 1

given:

m=10 kg

u=2m/s

v=5m/s

according to work energy theorem ,work done by a force on a moving body is equal to the increase in kinetic energy according to work

thus,work done

=increase in k.e

=>1/2mv²-1/2mu²

=>1/2*m(v²-u²)

=>1/2*10*(5²-2²)

=>5*21

=>105 j

Answer 2

Answer:

Explanation:

Given:-

m=10kg

u=2m/s

v=5m/s

Work done =Final K.E.- Initial K.E.

=1/2mv^2 - 1/2mu^2

=1/2m(v^2-u^2)

=1/2*10(5^2-2^2)

=1/2*10(25-4)

=1/2*10*21

=105J (Ans)

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