Question

A certain force acts on a body of mass 10kg and changes its velocity from 2 m/s to 5 m/s. Calculate the work done by the force

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Answer 1

Answer:

105

Explanation:

work done by force = change in kinetic energy

= 1/2 m Vf^2 - 1/2 m Vi^2

= 1/2 m ( Vf^2 - Vi^2)

= 1/2 * 10 (25-4)

= 105

Answer 2

$\huge \mathfrak \red{Answer:}$

$\sf{☞Given:}$

A certain force acts on a body of mass 10kg and changes its velocity from 2 m/s to 5 m/s.

$\sf{☞To \: find:}$

Work done by the force.

$\sf{☞Solved:}$

Here,

• m = 10kg
• u = 2m/s
• v = 5m/s

So, work = ∆KE

= 1/2 × m × v2² – 1/2 × m × v1²

= 1/2 × m × (v2² – v1²)

= 1/2 × 10 kg × ((5 m/s)² – (2 m/s)²)

= 5 kg × ((25-4) m²/s²

= 5 kg × 21 m²/s²

= 105 joules