Question

A certain force applied on a body for 2 sec increases its velocity from 1.5 m/s to 3 m/s. Later this same force is applied for 3 sec. What is the change in velocity in these 3 sec?

Answer 1

Answer:

the answer is 5.25m/s..............

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Answer 2

Answer:

Explanation:

The force applied for 2 sec changes the velocity from 1.5m/s to 3 m/s,

So, the acceleration produced by the force,

⇒v-u/t, where v=3,u=1.5 and t = 2,

⇒3-1.5/2,

⇒1.5/2,

⇒0.75,

⇒0.75m/s² is the acceleration produced.

⏩Now again the same force is applied after the body gains a velocity 3m/s , so it will produce the same acceleration, that is 0.75m/s² ,

⇒In this case, initial velocity (u) = 3m/s ,

⇒acceleration (a) = 0.75m/s² ,

⇒and time (t) = 3sec ,

Using the 1st equation of motion,

⇒v=u+at,

⇒v=3+3(0.75),

⇒v=6(0.75),

⇒4.5 m/s

Therefore, the velocity changes to 4.5 m/s.

Hope it helps you.