Question

A certain freezing process requires that the room temperature be lowered from 40°C at
the rate of 5°C every hour. What will be the room temperature 10 hours after the process
begins?​

Answer 1

Answer:

Here you go .........

Step-by-step explanation:

the temperature is lowered in an arithmetic progression. so we can apply formulae of an arithmetic progression.

initial temperature = a = 40°C

common difference d = -5°C per hour

after 10 hours temperature = $a_{10}$

$a_{n}$ = a + (n-1)d

n = 10hours = 10

a$_{n}$ = 40 + (10-1)(-5)

    = 40 -45

    = -5°C

Therefore the temperature after 10hours = -5°C

               Hope it helps you.

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