Question

a certain gas is contained at 1 atm at 10°C , n= 1g/mole find the certain volume of gas​

Answer 1

Step-by-step explanation:

For gaseous water PV=nRT

Thus, volume occupied by 1 mole gaseous water can be derived as (T=273+100=373K)

V=

P

nRT

=

1

1×0.0821×373

=30.62litre

Also, volume of 1 mole of liquid water = mass/ density

=

0.958

18

=18−79mL=18.79×10

−3

litre

Thus, volume percentage occupied by water molecules in gaseous state

=

30.62

18.79×10

−3

×100=0.0614

Percentage of free volume=100−0.0614=99.9386

so nearest integer value is 100.

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