Question

a train starts from delhi 6 am and reach ambala cant at 10 am and other train start from ambala cant 8 am and reach delhi 11:30 if the distance between ambala and step by step 2/7 kese aaya
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Answer 1

Answer:

Average speed of train leaving Delhi = 200/4=50 km/hr

Average speed of train leaving Ambala cantt. = 200 ×2/7=400/ 7

By the time the other train starts from Ambala cantt, the first train had travelled 100 km

Therefore, the trains meet after:

=200−100/(50+400/7)=14/15hr

=14/15×60=56minutes

Hence they meet at 8:56 am

Answer 2

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Average speed of train leaving Delhi = $\frac{200}{4}$ =50 km/hr

Average speed of train leaving Ambala cantt. = 200× $\frac{2}{7}$ = $\frac{400}{7}$

200/3.5 = 200*2/7 [where 3.5 is the time difference between 8am and & 11.30 am]

By the time the other train starts from Ambala cantt, the first train had travelled 100 km

Therefore, the trains meet after:

$\frac{200 - 100}{(50 + \frac{400}{7} )} = \frac{14}{15} \: hr$

$= \frac{14}{15} \times 60 = 56\:\:minutes$

Hence they meet at 8:56 am