Question

the de Broglie wavelength of the electron in the second bohr orbit is given the radius of a first orbit is 0.53 ampheres​

Answer 1

Answer:The de Broglie's wavelength of electron present in first Bohr orbit of 'H' atom is 2π×0.529

A

o

.

First Bohr orbit of 'H' atom has radius r=0.529A

o

Also, the angular momentum is quantised.

mvr=

2π

h

​

2πr=

mv

h

​

=λ

λ=2π×0.529

A

o

Explanation: