Question

A certain group of students uses the internet services for a monthly charge of Rs. 4,800. If 4 more students join the group,each person would be Rs. 200 less. Find the number of students in the group in the beginning.

Answer 1

Hey mate here is ur detailed answer...

Let total no. of stidents in beginning be x
Bill paid by each of them be y

Thus xy = 4800. (eq 1)
y = 4800/x. (eq 2)

ATQ. (x+4)(y-200) = 4800
xy - 200x + 4y - 800 = xy ( from eq 1 )
4y - 200x = 800
y - 50x = 200
4800/x - 50x = 200 ( from eq 2 )
4800 - 50x^2 = 200x
50x^2 + 200x - 4800 = 0
x^2 + 4x - 96 = 0
x^2 - 8x + 12x - 96 = 0 ( using middle term split method )
x(x-8) + 12(x-8) = 0
(x-8) (x+12) =0

x = 8, -12

x can't be negative thus x = 8

Answer 2

Answer: Therefore, 8 students were there in the begining.

Step-by-step explanation:

Let the total no. of students in the beginning be x.

let bill paid by each of them be y.

so, x*y = 4800.  

y = 4800/x.

As per the question

4 more students join the group and each person would be Rs. 200 less.

so, (x+4)(y-200) = 4800

x y - 200x + 4y - 800 = 0

4y - 200x = 800

y - 50x = 200            

4800/x - 50x = 200 (put the above eq)

4800 - 50x*2 = 200x

50x*2 + 200x - 4800 = 0

x*2 + 4x - 96 = 0

x*2 - 8x + 12x - 96 = 0

x(x-8) + 12(x-8) = 0

(x-8) (x+12) =0

x = 8, -12

x can be negative but as per our question the no. of students can't be negative so  x = 8.

Therefore, 8 students were there in the begining.

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