Question

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A certain laser transition emits 6.37 x 1015 quanta per second per square me
output in joule per square metre per second . Given a = 632.8 nm.
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Answer 1

Answer:

energy falling per sq m/sec=number of quanta falling/m^2/sec*energy of one quanta

=$6.37*10^{25} *h_{c} /lamda$

=$6.37*10^{25} *6.625*10^{-34} *3.0*10^{18} /632.8*10^{-9}$

Here the answer will cime in J/m^2/sec