A certain mass of nitrogen occupies 700 cm3 at a certain pressure. When the pressure becomes 28 atm it
occupies 1400 cm. Calculate the initial pressure if the temperature is kept constant.
Answers
Answer:
n is odd. II, §1, p. 24. 3. x negative, y positive 4. x negative, y negative. II, §3, p. ... (x - 2)2 + (y + 1)2 = 25 6. x 2 + (y - 1)2 = 9 7. (x + \)2 ... (a) 1 ftjsec (b) 1 ft/sec 10. ... (a) The point on the wall nearest to the light is when 0 = O. Then tan 0 = 0, so ... m n n ~-m. (If n = -m, use No. 86.) f . " .. sin"+1 ax cos,"-1 ax m - 1 f .
Explanation:
n is odd. II, §1, p. 24. 3. x negative, y positive 4. x negative, y negative. II, §3, p. ... (x - 2)2 + (y + 1)2 = 25 6. x 2 + (y - 1)2 = 9 7. (x + \)2 ... (a) 1 ftjsec (b) 1 ft/sec 10. ... (a) The point on the wall nearest to the light is when 0 = O. Then tan 0 = 0, so ... m n n ~-m. (If n = -m, use No. 86.) n is odd. II, §1, p. 24. 3. x negative, y positive 4. x negative, y negative. II, §3, p. ... (x - 2)2 + (y + 1)2 = 25 6. x 2 + (y - 1)2 = 9 7. (x + \)2 ... (a) 1 ftjsec (b) 1 ft/sec 10. ... (a) The point on the waln is odd. II, §1, p. 24. 3. x negative, y positive 4. x negative, y negative. II, §3, p. ... (x - 2)2 + (y + 1)2 = 25 6. x 2 + (y - 1)2 = 9 7. (x + \)2 ... (a) 1 ftjsec (b) 1 ft/sec 10. ... (a) The point on the wall nearest to the light is when 0 = O. Then tan 0 = 0, so ... m n n ~-m. (If n = -m, use No. 86.) f . " .. sin"+1 ax cos,"-1 ax m - 1 f .l nearest to the light is when 0 = O. Then tan 0 = 0, so ... m n n ~-m. (If n = -m, use No. 86.) f . " .. sin"+1 ax cos,"-1 ax m - 1 f .f . " .. sin"+1 ax cos,"-1 ax m - 1 f .