a certain nucleus X has a mass number 202 and atomic number 84. the nucleus X changes to 82Y198 after loss of particle. Name the particle emitted and represent the change in the form of an equation
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ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as:
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 6
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X →
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X → 7
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X → 714
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X → 714
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X → 714 Y+
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X → 714 Y+ −1
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X → 714 Y+ −10
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X → 714 Y+ −10
ANSWERHere, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 614 X → 714 Y+ −10 e
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