Math, asked by arunimaj4, 5 months ago

A certain number of men can do a work in 15
days working 8 h a day. If the number of men is
decreased by 1/3, then in how many days can twice the previous work be completed by the remaining
men working 5 h per day?​

Answers

Answered by charanimukku
0

Answer: Method-1 You have to just follow a simple concept- M1×D1×H1= M2×D2×H2 Where M is no. of Men, D is no. of days and H is for Hours. Now put all the given values in the above formula 12×10×8=M2×8×15 M2=8 Men If you are not getting this concept then f...

Step-by-step explanation:

Answered by fahadyaqub10
0

Answer:

73

Step-by-step explanation:

M1×D1×H1. M2×D2×H1

---------------- = ---------------

W1. W2

put the values and get answers

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