A certain number of men can finish a piece of work in 50 days. if there are 7 more men the work can be completed 10 days earlier. how many men were originally there?
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let a certain number of men be x
x men can work a job in 50 days
x men can work 1/50 job in 1 day
1 man can work 1/50x in 1 day..........................1
x+7 can do the same job in 40 days
similarly,
1 man can do 1/40(x+7) job in 1 day ..............2
from 1 and 2,
1/50x = 1/40(x+7)
solving the equation, x = 35 men.
x men can work a job in 50 days
x men can work 1/50 job in 1 day
1 man can work 1/50x in 1 day..........................1
x+7 can do the same job in 40 days
similarly,
1 man can do 1/40(x+7) job in 1 day ..............2
from 1 and 2,
1/50x = 1/40(x+7)
solving the equation, x = 35 men.
ibrah1m003:
i am not sure about the answer but it is correct until the second last step
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