A certain number of two digits is three times the sum of digits and if 45 is added to it digits afre reversed the number is
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Step-by-step explanation:
let the two digit number be xy
X is in tens place so we take =10x
Y is in the ones place ,so we take it y.
According to the given conditions, we have
10x+y=3(x+y)
7x-2y=0 ...(1)
After reverse the number, 10x+y+45=10y+x
x-y+5=0 ...(2)
Solving the equations (1) and (2), we get
7x - 2y =0
7x = 2y
x = 2y /7 .....(3)
x - y +5 =0
2y /7 -y + 5 =0 (putting value of equation 3 )
2y - 7y / 7 = -5
-5y /7 = -5
-5y = -35
y = 7 ...(4)
x - y +5 =0
x - 7 + 5 =0 (putting value of y equation 4)
x -2 =0
x = 2
y = 7 and x = 2
Thus, the number is 27.
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