Question

A certain number of two digits is three times the sum of digits and if 45 is added to it digits afre reversed the number is

Answer 1

Answer:

Step-by-step explanation:

let the two digit number be xy

X is in tens place so we take =10x

Y is in the ones place ,so we take it y.

According to the given conditions, we have

10x+y=3(x+y)

7x-2y=0     ...(1)

After reverse the number, 10x+y+45=10y+x

x-y+5=0               ...(2)

Solving the equations (1) and (2), we get

7x - 2y =0

7x = 2y

x = 2y /7         .....(3)

x - y +5 =0

2y /7 -y + 5 =0     (putting value of equation 3 )

2y - 7y / 7 = -5

-5y /7 = -5

-5y = -35

y = 7      ...(4)

x - y +5 =0

x - 7 + 5 =0      (putting value of y equation 4)

x -2 =0

x = 2

y = 7 and x = 2

Thus, the number is 27.