A certain pipe can fill up a tank 2 hours faster than another pipe. It takes 3 and hours for both pipes to fill up the same tank. In how many hours would the first pipe fill up the tank?
Answers
Answer:
I think in three hour I am not sure I think
Step-by-step explanation:
Let the faster pipe alone take x hours
Slower pipe alone will take (x+2) hours
Together in 1 hour they fill 1 / x + 1 / (x + 2) of the tank
Since together they take 3 hours, in 1 hour they fill 1/3 of tank
1 / x + 1 / (x + 2) = 1/3
3(x + 2) + 3x = x(x + 2)
x ^ 2 - 4x = 6
ADD 4
x ^ 2 - 4x + 4 = 10
(x - 2) ^ 2 = 10
x - 2 = 1/10
x= backslash 10 + 2 = 5.16 hours
faster pipe = 5.16 hours and slower one 7.16 hours
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Answer:
The first pipe filled up the tank in 2 hours.
Step-by-step explanation:
Let's assume that the hours taken by the first pipe to fill the tank is 'x'.
According to the question,
(x + x + 2)/2 = 3
⇒ 2x + 2 = 6
⇒ 2x = 4
⇒ x = 2
Hence, the time taken by the first pipe to fill the tank is 2 hours.
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